Steel Buildings in Europe
Title Worked Example: Compression Resistance 3 of 3 8 - 26 1.4. Torsional buckling N b,T,Rd L T = 3,8 m N crT = T 2 T w 2 z 0 1 GI L EI i i 0 2 = i y 2 + i z 2 = 204 2 + 43,1 2 = 43474 N crT = 4 2 9 2 89,3 10 81000 3800 10 1249 210000 43474 1 10 -3 = 5787 kN T = crT y N A f = 3 10 5787 235 11600 = 0,686 T = 0,5 [1 + α T ( T – 0,2) + 2 T ] The buckling curve for torsional buckling is the same as for minor axis buckling, therefore choose buckling curve b α z = 0,34 T = 0,5 (1 + 0,34 (0,686 - 0,2) + 0,686 2 ] = 0,818 χ T = 2 T 2 1 = 2 2 0,818 0,686 0,818 1 = 0,791 N b,T,Rd = M1 T y Af = 1,0 235 11600 0,791 10 -3 = 2156 kN
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